Anthony T. answered • 06/24/21

Patient Math & Science Tutor

If all the heat goes into the work of expanding the gas at constant pressure, the work done is p(V2 - V1).

Let's convert the external pressure to atmospheres 826.1mm / 760 mm = 1.087 atm.

We are given that 101.3 j = 1 L-atm, so the heat produced 427.8 j x 1L-atm /101.3 j = 4.223 L-atm.

Putting this into the first equation 4.223 L-atm = 1.087 atm (V2 L - 8.2 L) and solve for V2.

V2 = 12.08 L