Roger N. answered 06/22/21
. BE in Civil Engineering . Senior Structural/Civil Engineer
This is a problem of energy where potential energy is equal to the kinetic energy when you drop a ball. The potential energy of the spring PE = 1/ 2 kx2, and the kinetic energy of the puck KE= 1/2mv2, equating
PE = KE, 1/2 kx2 = 1/2 mv2 , kx2 = mv2, v2 = kx2/ m = 150 N/m ( 0.05m)2 / 0.005 kg = 75 m2/s2, v = 8.66 m/s