
Jon S. answered 06/22/21
Patient and Knowledgeable Math and English Tutor
Outcome Probability
0 C(3,0)*C(4,2)/C(7,2) = 6/21
1 C(3,1)*C(4,1)/C(7,2) = 12/21
2 C(3,2)/*C(4,0)/C(7,2) = 3/21
where C(x,y) is combinations of x items taken y at a time
Kozume S.
asked 06/21/21Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 black balls. Find the probability distribution of the number of black balls.
Jon S. answered 06/22/21
Patient and Knowledgeable Math and English Tutor
Outcome Probability
0 C(3,0)*C(4,2)/C(7,2) = 6/21
1 C(3,1)*C(4,1)/C(7,2) = 12/21
2 C(3,2)/*C(4,0)/C(7,2) = 3/21
where C(x,y) is combinations of x items taken y at a time
Alex L. answered 06/22/21
Experienced and licensed math educator w/ practical statistics exp.
Start by finding the size of the sample space. Note that this is without replacement. 7 balls first pick x 6 balls second pick = 42.
Zero black: 4/7 * 3/6 = 12/42
Two black: 3/7 * 2/6 = 6/42
One black: 42-12-6 = 24/42
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