Chemistry Question

Question

Determine the volume of a mixture of 0.04 mol of nitrogen and 0.001 mol of oxygen at SATP.

Answer 1

You need to use the ideal gas equation, PV = nRT.

In this case, the number of moles of gas is the sum of the number of moles of oxygen and nitrogen,

so n = 0.041 moles.

I assume SATP stands for standard pressure and temperature, P = 1 atm, T = 273 J.

So, solve the gas equation for V and substituting know values.

V = nRT / P = 0.041moles x 0.082 Latm/mole K x 273K / 1 atm = 0.9 liters

Answer 2

Hello Michael. Assuming that the problem is at STP, we can use the ideal gas equation: PV = nRT

At STP, temperature is 273 Kelvin and pressure is 1.00 atm.

The moles of nitrogen and oxygen may be added together to obtain a total number of moles of 0.041 mol.

PV = nRT

(1.00 atm)(V) = (0.041 mol)(0.08206 L x atm / mol x K)(273 K)

That is how the problem should be set up.