Calculate the calories needed to heat 6.4 g of water from 15°C to 34°C. Express your answer to two significant figures.

Answer 1

Hello Morgan. The equation needed for this problem is shown below:

heat = (mass) X (specific heat capacity) X (change in temperature)

Now let's plug in the data given in the problem. The specific heat of water is 1.0 cal/g x ^oC.

heat = (6.4g) X (1.0 cal/g x ^oC) X (19^oC)

heat = 120 calories