Calculate [OH−] [ O H − ] in the following aqueous solution at 25 ∘C ∘ C : [H3O+]= 2.5×10^-2 M

Answer 1

At 25^oC, [H₃O⁺] X [OH^-] = 1.0 x 10^-14M

So for this problem...

(2.5 x 10^-2M) X [OH^-] = 1.0 x 10^-14M

Of course, we simply divide to obtain the answer:

[OH^-] = 1.0 x 10^-14 / 2.5 x 10^-2M

[OH^-] = 4.0 x 10^-13M