Jacob N. answered 06/16/21
25 years of experience teaching high school chemistry!
Hello Katie. To solve this problem, we will use three-step stoichiometry. However, we must go through the three steps twice, first starting with the mass of N2, and then beginning with the mass of H2.
(5.00g N2) X (1 mol N2 / 28.02g) X (2 mol NH3 / 1 mol N2) x (17.031g / 1 mol NH3) = 6.08g NH3
(2.00g H2) X (1 mol H2 / 2.016g) X (2 mol NH3 / 3 mol H2) X (17.031g / 1 mol NH3) = 11.3g NH3
Of the two possible answers, we select the smaller...6.08g