Alex L. answered 06/15/21
Experienced and licensed math educator w/ practical statistics exp.
There's probably an easier way to do this, but...
Find each combined probability: that someone is ___ prepared AND answers all three questions correctly. These are dependent, of course. Questions are selected without replacement (so out of 20, then 19, then 18).
Very Well: 3/10 * 1 * 1 * 1 = 0.3
Well: 4/10 * 16/20 * 15/19 * 14/18 = 0.196
Mod Well: 2/10 etc. = 0.021
Poor: 1/10 etc. = 0.00088
Sum of those probabilities is 0.51788 (chance that anyone answered all three questions correctly)
Now we find the conditional probabilities:
Very Well IF all three correct: 0.3 / 0.51788 = 57.9%
Poor IF all three correct: 0.1 / 0.51788 = 0.17%

Alex L.
06/16/21
Leonard S.
Thank you friend. Regards06/15/21