What is the number of grams of propane, C3H8(g), required to produce 36 g of water vapor, H2O(g)?

Question

The balanced equation is: C3H8(g)+5O2(g)=3CO2(g)+4H2O(g)

Answer 1

Hello,

The balanced equation tells us we need 1 mole of propane to produce 4 moles of H₂O. We can determine the number of moles of water required for 36 grams. 36g/18 g/mole = 2 moles of water. We need 1/4 that number of moles of propane, so moles propane = 0.5 moles. Times it's molar mass of 44 g/mole, we find that we only need 11 grams of propane to produce 36 grams of water.

Bob