Jacob N. answered 06/14/21
25 years of experience teaching high school chemistry!
To solve a problem like this, we can multiply the mass of each isotope by the percentage abundance of that isotope...
52 amu X 0.8650 = 44.98 amu
49 amu X 0.0800 = 3.92 amu
50 amu X 0.0550 = 2.75 amu
Then add 44.98 amu + 3.92 amu + 2.75 amu = 51.65 amu.
The average atomic mass of element X is 51.65 amu.
Shelli T.
I want to thank you for posting, you helped me understand how to do this and I was struggling.01/21/23