Chemistry help plz show how you got your answer and work

Question

for the reaction: 2 KOH (aq) + CaCl2(aq) 2 KCl (aq) + Ca(OH)2(s) If you have 400 mL of a 1.5 M solution of CaCl2, how many grams of Ca(OH)2should theoretically be produced?

Answer 1

Hello Caleb!

This question can be turned into a stoic problem.

So this here is the reaction:

2 KOH (aq) + CaCl₂(aq) --> 2 KCl (aq) + Ca(OH)₂(s)

You are told that you have 400 mL of 1.5 M CaCl₂

The moles can be obtained by multiplying the concentration (in M) and volume (in L), (moles = M*V), so you have (1.5 M)(400/1000 L) = 0.6 mol CaCl₂

From the reaction, we know that 1 mole of CaCl₂ produces 1 mole of Ca(OH)₂ , because both have a coefficient of 1 in front of them

That means that 0.6 mol CaCl₂ will make 0.6 mol Ca(OH)₂.

Molar mass of Ca(OH)₂ = 74.09 g/mol, which can be used to convert moles to grams:

0.6 mol Ca(OH)₂ × (74.09 g Ca(OH)₂ /1 mol Ca(OH)₂) = 44.54 g Ca(OH)₂.