Jacob N. answered 06/11/21
25 years of experience teaching high school chemistry!
Good morning. Assuming that all other factors remain constant, doubling the Kelvin temperature of a gas does indeed double the pressure.
We can verify this by setting up the equation shown below:
(P1 / T1) = (P2 / T2)
The problem does not provide us with any pressure values, so we may arbitrarily select a value for P1. Let's say P1 was 1.00 atm.
(1.00 atm / 150 K) = (P2 / 300 K)
Clearly, P2 must be 2.00 atm.