Jacob N. answered 06/10/21
25 years of experience teaching high school chemistry!
Good morning. Let's go through these four questions one at a time.
a. To balance the equation, notice that the given equation has two atoms of chlorine and two atoms of sodium on the reactant side. However, the product side of the equation initially has only one atom of sodium and one atom of chlorine. Thus, to balance the equation, we can put a coefficient of 2 in front of NaCl.
b. To determine molar masses, you will need a periodic table and a calculator. The given formula shows us that calcium chloride contains one atom of calcium and two atoms of chlorine. We can set up the problem like this:
Ca: 1 X 40.08 g/mol = 40.08 g/mol
Cl: 2 X 35.45 g/mol = 70.90 g/mol
Then add 40.08 g/mol + 70.90 g/mol to get the molar mass of CaCl2.
(note: periodic tables will vary as to how many decimal places are given for atomic mass...)
c. solve this problem using the same strategy as in problem b.
d. to solve this problem, we need to use three-step stoichiometry...
30.0g CaCl2 X 1 mol CaCl2 / 110.98 g/mol X 1 mol CaC2O4 / 1 mol CaCl2 X the molar mass of CaC2O4, which you determine in problem c.