WHAT IS THE ANSWER?

Question

What would be the final temperature (C) of a rigid container with a pressure of 0.74 atm with an initial volume of 11.6 L at an original  temperature of -59.3 C when the pressure is changed to 1.17 atm and the volume changes to 5.9 L?

Answer 1

This is a combined gas law problem. The equation we can use is:

T₁ / P₁V₁ = T₂ / P₂V₂

The other thing we must do is convert Celsius temperature to Kelvin temperature. Always use Kelvins when working gas law problems. As you probably know, we change Celsius to Kelvin by adding 273 to the Celsius temperature.

213.7 K / (0.74 atm)(11.6 L) = T₂ / (1.17 atm)(5.9 L)

T₂ = 172 K

If the problem wants the answer in degrees Celsius, then convert 172 Kelvin to degrees Celsius.