Determine the mass of O2 needed if 17.4 mol Al2O3 are produced.

Question

Determine the mass of O₂ needed if 17.4 mol Al₂O₃ are produced.

Answer 1

The first step is to write out a balanced equation of the formation of Al2O3:

1. 4Al + 3O2 -> 2Al2O3

We can use this equation to convert the mols of aluminum oxide to mols of oxygen by looking at the mole ratio:

1. 17.4 mol Al2O3 x 3 mol O2 / 2 mol Al2O3 = 26.1 mol O2

Then we must convert the mols of O2 to grams because they want the solution in terms of mass (we can do this by multiplying the mols of O2 by oxygen's molecular mass):

1. 26.1 mol O2 x 96 g/mol = 2505.6 g

Final answer: 2505.6 g