How can i solve this equation

Question

Given the equation below, how many liters of hydrogen are needed to react with 60 L of nitrogen

3H₂ + N₂ -> 2NH₃

Answer 1

Hello, Kris,

We are not given any information on the conditions of pressure and temperature of the gases. We'll need to assume they are both at STP, or at least at equal conditions. All gases at STP occupy 22.4 Liters per mole of gas. 60 Liters of N₂ at STP represents 60L/22.4L/mole, or 2.68 moles N₂. The equation says we need 3 times that number of moles of hydrogen, or 8.04 moles of H₂. Convert that to Liters of H₂ by multiplying by (22.4 L/mole). I get 180 Liters of H₂. Note that 180 liters is 3 times the 60 liters of nitrogen.

Note that as long as the gases are under the same conditions, their volumes will be directly comparable to the moles of of that gas. 8.12345 ml of H₂ will have the same number of molecules as 8.12345 ml of C₄H₁₀, for example

Bob