Hello, Chloe,
We need the specific heat of water. There are several values that can be used, all equivalent, but with different units. I'll use 4.184 J/g*K.
This unit of specific heat says that if we add 4.184 Joules to 1 gram of water, it will raise it's temperature by 1 degree Kelvin. The temperature change of 8.9oC is also 8.9oK.
We can now calculate the heat we need by using the following expression:
q = C*M*(DT), where q is the heat/energy, C the specific heat, M the mass, and DT the temperature change (Delta T).
q = (4.184 J/g*K)*(780g)*(8.9K)
q = (4.184 J/g*K)*(780g)*(8.9K)
q = 29418 Joules, or 2.94 kJ
Bob

Robert S.
06/06/21
Chloe D.
What is joules? And can you break that down a little more for me?06/06/21