Mike D. answered 06/05/21
Effective, patient, empathic, math and science tutor
Suppose they have x, y and z and p in the purse
1st man
x + p + 2 (y + z)
2nd man
y + p = 3 (x + z)
3rd man
z + p = 5 (x + y)
This gives 3 equations in 4 unknowns (so no unique solution).
You can get x, y,z in terms of p.
[ from 1st equation write x = ....., then substitute for x in the 2nd and 3rd equation and solve for y,z in terms of p. Then find x in terms of p ]
I got : x=p/15, y = p/5, z = p/3