Hello, Kadie,
We use the ideal gas law to find the moles of CO2 under the specified conditions.
PV = nRT where n is the moles and R the gas constant, which was provided in the problem.
Rearrange to solve for the unknown, n:
n = PV/RT
Enter the data. The gas constant that is provided has units of L*atm*K−1⋅mol−1, and the data are consistent with these units, with the exception of temperatrure. We are given C, but we need Kelvin, as do most of the gas laws. Add 273.15 to 32C to obtain degrees K.
n = (1.03)(32.5L)/(0.821 L*atm*K−1⋅mol−1)(305.2K)
I get 1.34 moles CO2. At a molar mass of 44.0 g/mole, that is 58.8 grams of CO2.
Bob