2NH3---->N2 + 3 H2 i am asked : Starting with 25.0g NH3, how many grams of N2 are produced? Starting with 25.0g NH3, how many grams of H2 is produced? HELPPPP

Question

2NH3---->N2 + 3 H2

i am asked : Starting with 25.0g NH3, how many grams of N2 are produced?

Starting with 25.0g NH3, how many grams of H2 is produced?

HELPPPP

Answer 1

Our balanced equation is,

2NH3 ------> N2 + 3H2

As per this equation,

2 moles of ammonia gives 1 mol of N2 and 3 mol of H2.

We have 25.0 g NH3, convert this into no. of moles.

No. of moles of NH3 = mass/ Molar mass

No. of moles of NH3 = 25.0/17 = 1.47 mol

Thus, if 2 mol of NH3 gives 1 mol of N2 then,

1.47 mol NH3 will give = 1.47/2= 0.735 mol of N2

Thus, N2 in gram = 0.735 × 14 = 10.29 gm

In the same way,

If, 2 mol of NH3 gives 3 mol of H2 then

1.47 mol of NH3 will give = (1.47×3)/2 = 2.2 mol of H2

Thus, H2 in gm = 2.2 × 2 = 4.4 gm

So, answer is,

25.0 gm NH3 will give, 10.3 gm N2 and 4.40 gm H2