Inactive Tutor answered 06/03/21
Ok so the wording on this question is odd as it does not specify what direction the acceleration is in assuming it is horizontal W = Fd (if force is constant) and F = ma so W=mad = 22*2*15 = 660J
Riley D.
asked 06/03/21A boy pulls a rope attached to a 22 kg sled on an icy, frictionless surface with an acceleration of 2.0 m/s2. Calculate the work done by the boy if he is pulling the rope at 35° to the horizontal and for 15 m?
Inactive Tutor answered 06/03/21
Ok so the wording on this question is odd as it does not specify what direction the acceleration is in assuming it is horizontal W = Fd (if force is constant) and F = ma so W=mad = 22*2*15 = 660J
22*2*15=660 Joules
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