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Question

The reaction being observed is:

HCl + NH3 --> NH4Cl

If the Backyard Scientist added 5.9 grams of hydrochloric acid to excess ammonia and recovered 6.5 grams of NH4Cl, what was is the theoretical yield? What is the percent yield?

Answer 1

5.9 g HCl / 36.46g/mol = 0.16182 mol HCl

0.16182 mol HCl (1 mol NH4Cl / 1 mol HCl)= 0.16182 mol NH4Cl

0.16182 mol NH4Cl (63.491 g / 1 mol) = 10.27 g NH4Cl theoretical yield

%yield=(actual yield / theoretical yield)100

%yield=(6.5g/10.27g)100

%yield=63.3%