Outline the process you could use to identify three unlabeled solutions. One solution contains potassium ions another contains copper (I) ions, and the third has calcium ions present

Answer 1

Add Na₂SO₄(aq) to all three solutions.

One will form a white precipitate, CaSO₄(s), so that solution has Ca²⁺.

One will form a blue precipitate or a blue solution. That one has Cu²⁺.

The remaining one has potassium, K⁺. Na₂SO₄ doesn't react with K⁺, so nothing happens.