Mike D. answered • 06/03/21
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It depends on how far above the ground the bird is launched (that information is missing)
Mike D.
s = ut + 0.5at^2, s = 11, u = 0, a = 9.81 giving t = 0.75s. (time to hit the ground) The bird travels 38.7 m in 0,75s horizontally so initial velocity = 38.7/0.75 = 51.6 m/s horizontally.
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06/03/21
Ang B.
sorry!! it’s 11.0 meters06/03/21