height to fall = .5gT2=10000f
distance before target = vx*T= 300*5280/3600T feet ...
Solve system of equations to find x=19867 feet
Leah Anne F.
asked 06/02/21A bomb is dropped from an airplane travelling horizontally with a speed of 300 mph. If the airplane is 10,000 ft above the ground, how far from the target must it be released? Neglect air friction.
height to fall = .5gT2=10000f
distance before target = vx*T= 300*5280/3600T feet ...
Solve system of equations to find x=19867 feet
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