How many grams of Magnesium Hydroxide are needed to prepare 350.0 mL of a 0.600 M solution?

Answer 1

Magnesium hydroxide = Mg(OH)₂

Molarity = M = mol/L

0.600 M = 0.600 mol/L

350.0 mL = 0.35 L (there are 1000 mL in 1 L)

0.600 mol/L = x/0.35 L

x = 0.21 mol Mg(OH)₂

1 mol Mg(OH)₂ = 58.32 g/mol

(0.21 mol Mg(OH)₂)(58.32 g/mol Mg(OH)₂) = 12.25 g Mg(OH)₂

You need 12.25 grams of magnesium hydroxide to prepare 350 mL of a 0.600 M solution.