How many moles of HCl would have to be present to produce 75.82 g of MgCl2? Molar mass of MgCl2 = 95.21g

Question

Mg(OH)₂ (s) + 2 HCl (aq) --> 2 H₂O (l) + MgCl₂ (aq)

Answer 1

(75.82g MgCl₂) * (1 mole MgCl₂ /95.21g MgCl₂) * (2 mole HCl /1 mole MgCl₂) = 1.593 mole HCl.