Sidney P. answered 05/31/21
Astronomy, Physics, Chemistry, and Math Tutor
Compare the moles of rust that are produced: (4 mole Fe) * (2 mole Fe2O3 / 4 mole Fe) = 2 moles Fe2O3.
(4 mole O2) * (2 mole Fe2O3 / 3 mole O2) = 2.67 mole Fe2O3. So Fe is the limiting reactant and O2 the excess: there is not enough Fe to make 2.67 moles of product.