Sidney P. answered 05/28/21
Astronomy, Physics, Chemistry, and Math Tutor
(15.65g P4) * (1 mole P4 /123.90g P4) = 0.12632 mole of P4.
(0.12632 mole P4) * (4 mole PCl5 /1 mole P4) * (208.22g PCl5 /1 mole PCl5) = 105.2 grams of PCl5 produced.
(0.12632 mole of P4) * (10 mole Cl2 /1 mole P4) * (70.90g Cl2 /1 mole Cl2) = 89.56 grams of Cl2 consumed.