Amount of reactant that reacts with hydrochloric acid to produce aluminum chloride and 5.0.L of hydrogen gas at STP.

Question

Amount of reactant that reacts with hydrochloric acid to produce aluminum chloride and 5.0.L of hydrogen gas at STP.

Answer 1

At STP, (5.0 L gas) * (1 mole gas/ 22.4 L) = 0.22₃ mole H₂. Balanced reaction is 2 Al + 6 HCl --> 2 AlCl₃ + 3 H₂. Working backwards from this, (0.22₃ mole H₂) * (2 mole Al /3 mole H₂) * (26.98 g Al /1mole Al) = 4.0 g of reactant Al.