How many liters of Chlorine are needed to produce 5.64 moles of aluminum chloride?

Answer 1

First balance the synthesis reaction to get mole ratio: 2 Al + 3 Cl₂ --> 2 AlCl₃.

Dimensional analysis: (5.64 mole AlCl₃) * (3 mole Cl₂ /2 mole AlCl₃) = 8.46 mole Cl₂ gas.

IF we have STP, THEN (22.4 L/1 mole gas) * (8.46 mole Cl₂) = 190. L chlorine gas.

ELSE you would have to find volume from ideal gas law, V = nRT/P where n = 8.46 mole.