Find the vertex of the folloing equation

Question

y= 1/2x^2+2x-3

Answer 1

(y= 1/2)x^2 +2x - 3

2y = x^2 +4x -6

2y = 2^x2 +4x +4 -6 -4

2y =(x+4)^2 -10

y = (1/2)(x+4)^2 -5

vertex is (-4, -5)

(x-h)^2 -k where (h,k) = vertex, h=-4 and k=-5