Calculate the mass of the salt that can be produced from 10.0 g of magnesium chloride reacting with sulfuric acid. Include the percent yield of the salt if 11.5 g was actually produced.

Answer 1

Balance the reaction to get mole ratios: MgCl₂ + H₂SO₄ --> MgSO₄ + 2 HCl. Stoichiometry:

(10.0g MgCl₂) * (1 mole MgCl₂ /95.205g MgCl₂) * (1 mole MgSO₄ /1 mole MgCl₂) * (120.36g MgSO₄ /1 mole MgSO₄) = 12.6 g MgSO₄ salt, theoretically.

The percent yield is 100 * actual / theoretical = 100 * (11.5 / 12.6₄) = 91.0 %.