Calculate the specific heat when 15 grams of this material releases 375 J of heat when the temperature changes from 42.3 °C to 14.5 °C. Use specific heat to identify this material.

Answer 1

From Q = mcΔT, -375 J = (15 g) c (14.5 - 42.3), -375 = -417 c, c = 0.899 J /g °C. Probably aluminum.

Answer 2

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