Tom K. answered 05/24/21
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- As both of these functions are continuous at 0, you can just plug in 0 for x.
Girlie S.
asked 05/24/21i need help finding these limits
limx→0 : -2 sin 3x
limx→0 : 4cos2x
Tom K. answered 05/24/21
Knowledgeable and Friendly Math and Statistics Tutor
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Girlie S.
i got 0 for the first one and 4 for the second, i have to defend my answer so it would be they exist because the first one is continious at 0 while the other is at 4?05/24/21