How many grams of Magnesium Hydroxide are needed to prepare 350 mL of a 0.600M solution?

Answer 1

Using dimensional analysis and watching the units, (0.600 mole/L) * (0.350 L) = 0.210 mole. [0.210 mole Mg(OH)₂] * [58.32g Mg(OH)₂ /1 mole Mg(OH)₂] = 12.2 g Mg(OH)₂.