y=a(x-3)^2 +45
0=9a+45
a=-5
y=-5(x-3)^2 +45 in vertex form
y=-5x^2 +30x in standard form
Oliver P.
asked 05/23/21I have a downwards facing parabola with:
X intercepts (0,0) and (6,0)
Vertex: (3,45)
How do I get the equation in standard form
y=a(x-3)^2 +45
0=9a+45
a=-5
y=-5(x-3)^2 +45 in vertex form
y=-5x^2 +30x in standard form
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.