Todd W. answered • 05/22/21

Recent College Graduate Specializing Biology Tutoring

1)

7.6 mol CO2 x (5 mol O2 / 3 mol CO2) = **12.7 mol O2**

2)

13.4 g H2O x (1 mol C3H8 / 4 mol H2O) = 3.4 mol C3H8

3.4 mol C3H8 x (44.1g / mol) = **150g C3H8**

3)

31.2L O2 / 22.4 = 1.39 mol O2 x (3 mol CO2 / 5 mol O2) = 0.83 mol CO2

0.83 mol CO2 x 22.4 = **18.6L CO2**

4)

8298g C3H8 x (mol / 44.1g) = 188 mol C3H8 x (4 mol H2O / 1 mol C3H8) = 752 mol H2O

752 mol H2O x 22.4 = **16845L H2O**

**The last answer (4) seems very high to me, but I am fairly confident I have done it correctly, so I would both double check the date from the problem and try to do this one yourself as well. But I hope this helps a little bit. Let me know if you need a further explanation for how to do these.