Inactive Tutor answered 05/22/21
The mean will be normally distributed with mean = 45, standard deviation = 18 / √50
p ( 40 < mean < 48)
normalcdf
lower = 40
upper = 48
mean = 45
standard deviation= 18 / √50
Nisha J.
asked 05/22/21The lifetimes of a certain brand of battery have a mean of 45 hours and a
standard deviation of 18.
Find the probability that the mean lifetime of a random of such 50
batteries will be between 40 and 48 hours.
Inactive Tutor answered 05/22/21
The mean will be normally distributed with mean = 45, standard deviation = 18 / √50
p ( 40 < mean < 48)
normalcdf
lower = 40
upper = 48
mean = 45
standard deviation= 18 / √50
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