Night S.
asked • 05/21/210.50g calcium hydroxide
397.6g aluminum sulfate
Sidney P. answered • 05/22/21
Astronomy, Physics, Chemistry, and Math Tutor
Dimensional analysis: [0.50g Ca(OH)2] * [1 mole Ca(OH)2 / 74.09g Ca(OH)2] = 0.0067 mole calcium hydroxide.
[397.6g Al2(SO4)3] * [1 mole Al2(SO4)3 / 342.15g Al2(SO4)3] = 1.169 mole aluminum sulfate.
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