If 93.4 grams of aluminum react with copper (II) nitrate to produce aluminum nitrate and copper, how many grams of copper can be produced during this reaction?

Answer 1

First balance the reaction to get mole ratios: 2 Al + 3 Cu(NO₃)₂ --> 2 Al(NO₃)₃ + 3 Cu.

Then (93.4g Al) * (1 mole Al /26.98g Al) * (3 mole Cu /2 mole Al) * (63.55g Cu / 1 mole Cu) = 330. g Cu.