What pressure is required to compress 196.0 liters of air at 1.00 atm into a cylinder whose volume is 26.0 liters? (7.5 L)

Answer 1

From the ideal gas law, for the same amount n of gas, P₂V₂ / P₁V₁ = T₂ / T₁. At constant T, P₂ = P₁V₁ / V₂ = (1.00 atm) (196.0 L) / (26.0 L) = 7.54 atm.

The "(7.5 L)" at the end of your question was apparently the answer in atm, though there really are 3 sig figs here.