
Paul J. answered 05/21/21
Bachelor's of Science in Forensic Chemistry
Hi Skylre,
First we have to write a balanced reaction equation:
N2H4 + O2 -> N2 + 2 H2O
Next we have to determine our limiting reactant. Our limiting reactant is going to be the substance that is 100% consumed by the time our reaction has completed. Before doing any further calculations, it is easiest to convert the masses of each reactant into molar quantities first.
1,000 g N2H4 (1 mole / 32.05 grams) = 31.2 moles of hydrazine are available
1,200 g O2 (1 mole / 31.98 grams) = 37.5 moles of O2 are available
Now to determine our limiting reactant, we must determine how many moles of one reactant are needed to completely consume the other reactant:
Let's assume all of our hydrazine is consumed (using the coefficients from the balanced equation):
31.2 moles hydrazine (1 mole O2 / 1 mole hydrazine)
= 31.2 moles of O2 required to completely consume all of our hydrazine
Now let's assume all of our oxygen is consumed:
37.5 moles of O2 (1 mole hydrazine / 1 mole O2)
= 37.5 moles of hydrazine required to completely consume all of our oxygen
Now look back to the molar quantities of each reactant that we have available for this reaction. If all of our hydrazine was used up, we would need 31.2 moles of oxygen to consume all of it (and we have 37.5 moles of oxygen available). If all of our oxygen was used up, we would need 37.5 moles of hydrazine to consume all of it (which is not possible because we only have 31.2 moles of hydrazine available). Since we have enough oxygen to consume all of our hydrazine, but not enough hydrazine to consume all of our oxygen, we know that hydrazine is our limiting reactant and we will have an excess of oxygen at the end of the reaction.
So using the moles of hydrazine, we can calculate the moles of N2 formed, and then the volume:
(remember that 1 mole of gas will occupy approximately 22.4 liters at STP).
31.2 moles hydrazine (1 mole N2 / 1 mole hydrazine) ( 22.4 liters / 1 mole of N2)
= 698.88 L of N2 should be produced from this reaction