Callyn W.

asked • 05/20/21

Calculate the delta H for 2N2 + 5O2 = 2N2O5

Given the following data:

2NO + O2 = 2NO2 delta H= -114.1kJ

4NO + O2 = 2N2O5 delta H= -110.2kJ

N2 + O2 = 2NO delta H= 180.5kJ

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