
Billy M. answered 05/20/21
Need a math tutor? I am a local Albany State Univ. math tutor
P(x) =k (x - 5)(x - (-4 - 3i))(x - (-4 + 3i))
p(x)=-5(x^3+3x^2-15x-125)
p(x)=-5x^3-15x^2+75x+625
Lanio O.
asked 05/20/21Give an expression for f(x) with leading coefficient −5, of degree 3, and having roots x=5 , x=−4−3i, and x=−4+3i.
My answer was x^3+3x^2-15x-125 which is incorrect
Billy M. answered 05/20/21
Need a math tutor? I am a local Albany State Univ. math tutor
P(x) =k (x - 5)(x - (-4 - 3i))(x - (-4 + 3i))
p(x)=-5(x^3+3x^2-15x-125)
p(x)=-5x^3-15x^2+75x+625
Looks like you found the right polynomial, P(x) that has the roots specified, but P(x) * constant will also have the same roots.
They said that the leading term is -5, so multiply every term by -5.
Take care.
Kurt C. answered 05/20/21
Math, Science & Computer tutor
You have half of it correct. Your solution meets the requirements that x=5, x=-4-3i and x=-4+3i.
However, the other requirement is that the leading coefficient equals -5.
To accomplish this, just multiply your answer by -5, giving:
f(x) = -5x^3 -15x^2 +75x+625
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Lanio O.
thank you!!05/20/21