I got wrong answer for this question but it's close to choice e is this correct?

Question

Magnesium metal reacts with hydrochloric acid to form magnesium chloride and hydrogen gas. Suppose we react an excess of magnesium metal with 19.0 mL of a 3.00 M solution of hydrochloric acid and collect all of the hydrogen in a balloon at 25oC and 1.00 atm. What is the expected volume of the balloon?

a. 0.310 L

b. 0.0585 L

c. 0.697 L

d. 58.5 L

e. 1.39 L

Answer 1

Start with the extensive (depends on how much stuff) variable given (in this case, ml of acid) and cancel factors until you get to moles of H₂ or volume of H₂

Make sure you have the stoichiometry right: Mg(s) + 2HCl(aq) --> MgCl₂(aq) + H₂(g)

19 ml HCl soln * (1 liter/1000ml)(3 mole HCl/liter soln)(1 mole H₂/2 moles HCl) = moles of H₂

Use IGL to solve for volume or use 24.5 liters/mole of gas at 25 degrees C (It's a cousin of the 22.4 liters/mole at STP)

I get .698 liters (Looks like you missed the stoichiometry)