How many moles are in 2.58 g of silver nitrate? Part 2: How many molecules are in 2.58 g of silver nitrate?

Question

I need help with figuring the moles and molecules like I get confused with the equations. Can someone help me out please.

Answer 1

You don't need equations for this, just dimensional analysis (setting up conversion factors so that the final units are what you want. 1) (2.58 g AgNO₃) * (1 mole AgNO₃ / 169.9 g AgNO₃) = 0.0152 mole AgNO₃.

2) (0.0152 mole AgNO₃) * (6.02 x 10²³ molecules AgNO₃ / 1 mole AgNO₃) = 9.15 x 10²¹ molecules AgNO₃.