Chemistry Question 15

Question

Using the Ideal Gas Law and the given measurements, solve for the unknown variable.

How many moles of Rn are in a 63.353 L container at 5.8102 atm and 527 K?

 

Remember:

PV = nRT

R= 0.0821 atm•L/mol•K

Answer 1

The general Ideal Gas Law formula is

PV = nRT

For this scenario you want to solve for the number of moles (n) and then plug in the values that you know from the information given in the question

n = PV / RT

n = (5.8102 x 63.353) / (0.08206*527) = 8.5117 mol

meaning that there are 8.5117 moles of Radon (Rn) in the container

Answer 2

First step, plug in the numbers you are given into the equation. Here you are given a volume (63.353 L), a pressure (5.8102 atm), and a temperature (527 K).

PV = nRT

(5.8102 atm) x (63.353 L) = n x (0.0821 Latm/molK) x (527 K)

Second step, multiply the numbers together on each side to simplify the equation.

On the left side of the equation: 5.8102 x 63.353 = 368.09

On the right side of the equation: 0.0821 x 527 = 43.3

368.09 = 43.3 x n

Third step, divide to solve for n (the mole of Radon).

368.09/ 43.3 = 8.50 moles of Rn

Final Answer: 8.50 moles of Rn

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