Sidney P. answered • 05/19/21
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From Q = m c ΔT, 601 J = m (0.450 J/g °C) ( 120.0 - 22.5) = 43.9 m, m = 13.7 g of Fe.
Emi M.
asked • 05/18/21If 601 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C) that can be heated from 22.5°C to 120.0°C?
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