Determine the mass of Cu(No3)2 if 5.00 grams of copper react with silver nitrate.

Question

Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

Answer 1

5.00g Cu (mol / 63.546g) = 0.0787 mol Cu

0.0787 mol Cu (1 mol Cu(NO₃)₂ / 1 mol Cu) = 0.0787 mol Cu(NO₃)₂

0.0787 mol Cu(NO₃)₂ (187.56g / mol) = 14.8g Cu(NO₃)₂